How to pass parameters in the function in C
In c we can pass the parameters in a function in two different ways.
(a)Pass by value: In this approach we pass copy of actual variables in function as a parameter. Hence any modification on parameters inside the function will not reflect in the actual variable. For example:
#include<stdio.h>
int main(){
int a=5,b=10;
swap(a,b);
printf("%d %d",a,b);
return 0;
}
void swap(int a,int b){
int temp;
temp =a;
a=b;
b=temp;
}
Output: 5 10
(b)Pass by reference: In this approach we pass memory address actual variables in function as a parameter. Hence any modification on parameters inside the function will reflect in the actual variable. For example:
#incude<stdio.h>
int main(){
int a=5,b=10;
swap(&a,&b);
printf("%d %d",a,b);
return 0;
}
void swap(int *a,int *b){
int *temp;
*temp =*a;
*a=*b;
*b=*temp;
}
Output: 10 5
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